128=(4^2x)x(2^x)

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Solution for 128=(4^2x)x(2^x) equation: 



128=(4^2x)x(2^x)

We move all terms to the left:

128-((4^2x)x(2^x))=0

determiningTheFunctionDomain
-4^2xx2^x+128=0

We move all terms containing x to the left, all other terms to the right

-4^2xx2^x=-128

x=-128/1

x=-128

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